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0.8x^2=30
We move all terms to the left:
0.8x^2-(30)=0
a = 0.8; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·0.8·(-30)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*0.8}=\frac{0-4\sqrt{6}}{1.6} =-\frac{4\sqrt{6}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*0.8}=\frac{0+4\sqrt{6}}{1.6} =\frac{4\sqrt{6}}{1.6} $
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